x=10x^2+60x-10

Solution for x=10x^2+60x-10 equation:

x=10x^2+60x-10

We move all terms to the left:

x-(10x^2+60x-10)=0

We get rid of parentheses

-10x^2+x-60x+10=0

We add all the numbers together, and all the variables

-10x^2-59x+10=0

a = -10; b = -59; c = +10;
Δ = b2-4ac
Δ = -592-4·(-10)·10
Δ = 3881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-\sqrt{3881}}{2*-10}=\frac{59-\sqrt{3881}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+\sqrt{3881}}{2*-10}=\frac{59+\sqrt{3881}}{-20}
$